/*
 * Copyright (c) 1997, 2008, Oracle and/or its affiliates. All rights reserved.
 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
 *
 * This code is free software; you can redistribute it and/or modify it
 * under the terms of the GNU General Public License version 2 only, as
 * published by the Free Software Foundation.  Oracle designates this
 * particular file as subject to the "Classpath" exception as provided
 * by Oracle in the LICENSE file that accompanied this code.
 *
 * This code is distributed in the hope that it will be useful, but WITHOUT
 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
 * version 2 for more details (a copy is included in the LICENSE file that
 * accompanied this code).
 *
 * You should have received a copy of the GNU General Public License version
 * 2 along with this work; if not, write to the Free Software Foundation,
 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
 *
 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
 * or visit www.oracle.com if you need additional information or have any
 * questions.
 */


/*
 * The Original Code is HAT. The Initial Developer of the
 * Original Code is Bill Foote, with contributions from others
 * at JavaSoft/Sun.
 */

package com.sun.tools.hat.internal.util;
import java.util.*;

Author: Bill Foote
/** * A singleton utility class that sorts a vector. * <p> * Use: * <pre> * * Vector v = <a vector of, say, String objects>; * VectorSorter.sort(v, new Comparer() { * public int compare(Object lhs, Object rhs) { * return ((String) lhs).compareTo((String) rhs); * } * }); * </pre> * * @author Bill Foote */
public class VectorSorter {
Sort the given vector, using c for comparison
/** * Sort the given vector, using c for comparison **/
static public void sort(Vector<Object> v, Comparer c) { quickSort(v, c, 0, v.size()-1); }
Sort a vector of strings, using String.compareTo()
/** * Sort a vector of strings, using String.compareTo() **/
static public void sortVectorOfStrings(Vector<Object> v) { sort(v, new Comparer() { public int compare(Object lhs, Object rhs) { return ((String) lhs).compareTo((String) rhs); } }); } static private void swap(Vector<Object> v, int a, int b) { Object tmp = v.elementAt(a); v.setElementAt(v.elementAt(b), a); v.setElementAt(tmp, b); } // // Sorts v between from and to, inclusive. This is a quick, off-the-top- // of-my-head quicksort: I haven't put any thought into optimizing it. // I _did_ put thought into making sure it's safe (it will always // terminate). Worst-case it's O(n^2), but it will usually run in // in O(n log n). It's well-behaved if the list is already sorted, // or nearly so. // static private void quickSort(Vector<Object> v, Comparer c, int from, int to) { if (to <= from) return; int mid = (from + to) / 2; if (mid != from) swap(v, mid, from); Object pivot = v.elementAt(from); // Simple-minded, but reasonable int highestBelowPivot = from - 1; int low = from+1; int high = to; // We now move low and high toward eachother, maintaining the // invariants: // v[i] <= pivot for all i < low // v[i] > pivot for all i > high // As long as these invariants hold, and every iteration makes // progress, we are safe. while (low <= high) { int cmp = c.compare(v.elementAt(low), pivot); if (cmp <= 0) { // v[low] <= pivot if (cmp < 0) { highestBelowPivot = low; } low++; } else { int c2; for (;;) { c2 = c.compare(v.elementAt(high), pivot); // v[high] > pivot: if (c2 > 0) { high--; if (low > high) { break; } } else { break; } } // At this point, low is never == high if (low <= high) { swap(v, low, high); if (c2 < 0) { highestBelowPivot = low; } low++; high--; } } } // Now we just need to sort from from..highestBelowPivot // and from high+1..to if (highestBelowPivot > from) { // pivot == pivot, so ensure algorithm terminates swap(v, from, highestBelowPivot); quickSort(v, c, from, highestBelowPivot-1); } quickSort(v, c, high+1, to); } }