package com.fasterxml.jackson.core.io;

import java.math.BigDecimal;

public final class NumberInput
{
    
Textual representation of a double constant that can cause nasty problems
with JDK (see http://www.exploringbinary.com/java-hangs-when-converting-2-2250738585072012e-308).
/**
     * Textual representation of a double constant that can cause nasty problems
     * with JDK (see http://www.exploringbinary.com/java-hangs-when-converting-2-2250738585072012e-308).
     */
    public final static String NASTY_SMALL_DOUBLE = "2.2250738585072012e-308";

    
Constants needed for parsing longs from basic int parsing methods
/**
     * Constants needed for parsing longs from basic int parsing methods
     */
    final static long L_BILLION = 1000000000;

    final static String MIN_LONG_STR_NO_SIGN = String.valueOf(Long.MIN_VALUE).substring(1);
    final static String MAX_LONG_STR = String.valueOf(Long.MAX_VALUE);

    
Fast method for parsing integers that are known to fit into
regular 32-bit signed int type. This means that length is
between 1 and 9 digits (inclusive)

Note: public to let unit tests call it
/**
     * Fast method for parsing integers that are known to fit into
     * regular 32-bit signed int type. This means that length is
     * between 1 and 9 digits (inclusive)
     *<p>
     * Note: public to let unit tests call it
     */
    public static int parseInt(char[] ch, int off, int len)
    {
        int num = ch[off + len - 1] - '0';
        
        switch(len) {
        case 9: 
          num += (ch[off++] - '0') * 100000000;
        case 8: 
          num += (ch[off++] - '0') * 10000000;
        case 7: 
          num += (ch[off++] - '0') * 1000000;
        case 6: 
          num += (ch[off++] - '0') * 100000;
        case 5: 
          num += (ch[off++] - '0') * 10000;
        case 4: 
          num += (ch[off++] - '0') * 1000;
        case 3: 
          num += (ch[off++] - '0') * 100;
        case 2: 
          num += (ch[off] - '0') * 10;
        }
        return num;
    }

    
Helper method to (more) efficiently parse integer numbers from
String values.
/**
     * Helper method to (more) efficiently parse integer numbers from
     * String values.
     */
    public static int parseInt(String s)
    {
        /* Ok: let's keep strategy simple: ignoring optional minus sign,
         * we'll accept 1 - 9 digits and parse things efficiently;
         * otherwise just defer to JDK parse functionality.
         */
        char c = s.charAt(0);
        int len = s.length();
        boolean neg = (c == '-');
        int offset = 1;
        // must have 1 - 9 digits after optional sign:
        // negative?
        if (neg) {
            if (len == 1 || len > 10) {
                return Integer.parseInt(s);
            }
            c = s.charAt(offset++);
        } else {
            if (len > 9) {
                return Integer.parseInt(s);
            }
        }
        if (c > '9' || c < '0') {
            return Integer.parseInt(s);
        }
        int num = c - '0';
        if (offset < len) {
            c = s.charAt(offset++);
            if (c > '9' || c < '0') {
                return Integer.parseInt(s);
            }
            num = (num * 10) + (c - '0');
            if (offset < len) {
                c = s.charAt(offset++);
                if (c > '9' || c < '0') {
                    return Integer.parseInt(s);
                }
                num = (num * 10) + (c - '0');
                // Let's just loop if we have more than 3 digits:
                if (offset < len) {
                    do {
                        c = s.charAt(offset++);
                        if (c > '9' || c < '0') {
                            return Integer.parseInt(s);
                        }
                        num = (num * 10) + (c - '0');
                    } while (offset < len);
                }
            }
        }
        return neg ? -num : num;
    }
    
    public static long parseLong(char[] ch, int off, int len)
    {
        // Note: caller must ensure length is [10, 18]
        int len1 = len-9;
        long val = parseInt(ch, off, len1) * L_BILLION;
        return val + (long) parseInt(ch, off+len1, 9);
    }

    public static long parseLong(String s)
    {
        /* Ok, now; as the very first thing, let's just optimize case of "fake longs";
         * that is, if we know they must be ints, call int parsing
         */
        int length = s.length();
        if (length <= 9) {
            return (long) parseInt(s);
        }
        // !!! TODO: implement efficient 2-int parsing...
        return Long.parseLong(s);
    }
    
    
Helper method for determining if given String representation of
an integral number would fit in 64-bit Java long or not.
Note that input String must NOT contain leading minus sign (even
if 'negative' is set to true).
Params:
negative – Whether original number had a minus sign (which is
   NOT passed to this method) or not/**
     * Helper method for determining if given String representation of
     * an integral number would fit in 64-bit Java long or not.
     * Note that input String must NOT contain leading minus sign (even
     * if 'negative' is set to true).
     *
     * @param negative Whether original number had a minus sign (which is
     *    NOT passed to this method) or not
     */
    public static boolean inLongRange(char[] ch, int off, int len,
            boolean negative)
    {
        String cmpStr = negative ? MIN_LONG_STR_NO_SIGN : MAX_LONG_STR;
        int cmpLen = cmpStr.length();
        if (len < cmpLen) return true;
        if (len > cmpLen) return false;

        for (int i = 0; i < cmpLen; ++i) {
            int diff = ch[off+i] - cmpStr.charAt(i);
            if (diff != 0) {
                return (diff < 0);
            }
        }
        return true;
    }

    
Similar to inLongRange(char[], int, int, boolean), but with String argument 
Params:
negative – Whether original number had a minus sign (which is
   NOT passed to this method) or not/**
     * Similar to {@link #inLongRange(char[],int,int,boolean)}, but
     * with String argument
     *
     * @param negative Whether original number had a minus sign (which is
     *    NOT passed to this method) or not
     */
    public static boolean inLongRange(String s, boolean negative)
    {
        String cmp = negative ? MIN_LONG_STR_NO_SIGN : MAX_LONG_STR;
        int cmpLen = cmp.length();
        int alen = s.length();
        if (alen < cmpLen) return true;
        if (alen > cmpLen) return false;

        // could perhaps just use String.compareTo()?
        for (int i = 0; i < cmpLen; ++i) {
            int diff = s.charAt(i) - cmp.charAt(i);
            if (diff != 0) {
                return (diff < 0);
            }
        }
        return true;
    }

    public static int parseAsInt(String s, int def)
    {
        if (s == null) {
            return def;
        }
        s = s.trim();
        int len = s.length();
        if (len == 0) {
            return def;
        }
        // One more thing: use integer parsing for 'simple'
        int i = 0;
        if (i < len) { // skip leading sign:
            char c = s.charAt(0);
            if (c == '+') { // for plus, actually physically remove
                s = s.substring(1);
                len = s.length();
            } else if (c == '-') { // minus, just skip for checks, must retain
                ++i;
            }
        }
        for (; i < len; ++i) {
            char c = s.charAt(i);
            // if other symbols, parse as Double, coerce
            if (c > '9' || c < '0') {
                try {
                    return (int) parseDouble(s);
                } catch (NumberFormatException e) {
                    return def;
                }
            }
        }
        try {
            return Integer.parseInt(s);
        } catch (NumberFormatException e) { }
        return def;
    }

    public static long parseAsLong(String s, long def)
    {
        if (s == null) {
            return def;
        }
        s = s.trim();
        int len = s.length();
        if (len == 0) {
            return def;
        }
        // One more thing: use long parsing for 'simple'
        int i = 0;
        if (i < len) { // skip leading sign:
            char c = s.charAt(0);
            if (c == '+') { // for plus, actually physically remove
                s = s.substring(1);
                len = s.length();
            } else if (c == '-') { // minus, just skip for checks, must retain
                ++i;
            }
        }
        for (; i < len; ++i) {
            char c = s.charAt(i);
            // if other symbols, parse as Double, coerce
            if (c > '9' || c < '0') {
                try {
                    return (long) parseDouble(s);
                } catch (NumberFormatException e) {
                    return def;
                }
            }
        }
        try {
            return Long.parseLong(s);
        } catch (NumberFormatException e) { }
        return def;
    }
    
    public static double parseAsDouble(String s, double def)
    {
        if (s == null) { return def; }
        s = s.trim();
        int len = s.length();
        if (len == 0) {
            return def;
        }
        try {
            return parseDouble(s);
        } catch (NumberFormatException e) { }
        return def;
    }

    public static double parseDouble(String s) throws NumberFormatException {
        // [JACKSON-486]: avoid some nasty float representations... but should it be MIN_NORMAL or MIN_VALUE?
        /* as per [JACKSON-827], let's use MIN_VALUE as it is available on all JDKs; normalized
         * only in JDK 1.6. In practice, should not really matter.
         */
        if (NASTY_SMALL_DOUBLE.equals(s)) {
            return Double.MIN_VALUE;
        }
        return Double.parseDouble(s);
    }

    public static BigDecimal parseBigDecimal(String s) throws NumberFormatException {
        try { return new BigDecimal(s); } catch (NumberFormatException e) {
            throw _badBD(s);
        }
    }

    public static BigDecimal parseBigDecimal(char[] b) throws NumberFormatException {
        return parseBigDecimal(b, 0, b.length);
    }
    
    public static BigDecimal parseBigDecimal(char[] b, int off, int len) throws NumberFormatException {
        try { return new BigDecimal(b, off, len); } catch (NumberFormatException e) {
            throw _badBD(new String(b, off, len));
        }
    }

    private static NumberFormatException _badBD(String s) {
        return new NumberFormatException("Value \""+s+"\" can not be represented as BigDecimal");
    }
}